Is there a more efficient way to remove items from a list based on another list?

PUNCT_CHARS = { '（', '）', ',', '，', '、', ':', '：', '[', ']', '#'}

words = ['a', '#good', 'student']

for word in words.copy():
    for char in PUNCT_CHARS:
        if char in word:
            words.remove(word)
            break

print(words)

['a', 'student']

I want to remove words that contain punctuations. Can the 2nd for loop be replaced with an ‘any’ or ‘all’ function to make it more efficient?

>Solution :

Take advantage of your PUNCT_CHARS set to check if the sets of characters are disjoint:

out = [w for w in words if PUNCT_CHARS.isdisjoint(w)]

Output: ['a', 'student']

To modify your original object:

words[:] = [w for w in words if PUNCT_CHARS.isdisjoint(w)]