Is there a way i could end a loop with a char in c++?

March 18, 2022

I am new to programming, and I am currently trying to figure my way around C++. I am working on a program that will display basic information about employees to the users, and I want the program to end when the users entered a char. However, while working through it, I encountered a problem. When I enter the char (x), it somehow looped from 1-120 (as you seen in the counter below), but when I entered its ASCII number (120), it ended the program as intended. Can anyone explain it to me and what are the possible solutions?

#include <iomanip>
#include <iostream>

using namespace std;
class Employee
{
public:
    int Age;
    string Name;
    int ID;

    void information()
    {
        cout << "Name: " << Name << endl;
        cout << "Age: " << Age << endl;
        cout << "ID: " << setfill('0') << setw(3) << ID << endl;
    }

    Employee(string name, int age, int id)
    {
        Name = name;
        Age = age;
        ID = id;
    }
};

void createProfile()
{
    int age;
    int id;
    string name;
    cout << "Enter the Employee Name: ";
    cin >> name;
    cout << "Enter the Employee Age: ";
    cin >> age;
    cout << "Enter the Employee ID: ";
    cin >> id;
}
int main()
{
    int num, counter;
    const char stop = 'x';

    cout << "Choose an Employee " << endl;
    cout << "001 Jack" << endl;
    cout << "002 Susan" << endl;
    cout << "003 to create profile" << endl;
    cout << "Press x to Exit";
    for (num = 0; num != stop; num++)
    {
        cout << "\n\nEnter the Employee ID: ";
        cin >> num;
        counter += 1;
        if (num == 001)
        {
            Employee jack = Employee("Jack", 25, 001);
            jack.information();
        }
        else if (num == 002)
        {
            Employee jack = Employee("Susan", 23, 002);
            jack.information();
        }
        else if (num == 003)
        {
            createProfile();
        }
        else
        {
            cout << "Input invalid";
        }
    }
    cout << "\n" << counter;
}

>Solution :

Yes, of course. In C/C++, char is a type that can be represented either by its character value ('A', for example) or its numeric value (65). However, a digit’s numeric value does not equal to itself.

'1' == 49

120 is the ASCII value of lower case x and since you loop with an int, it is logical that it will end up working in ways you do not expect it to work. You can change your