Iterate over set and remove element if it is in another set and return array

I am not sure what I am missing from my function here to remove elements in a a set. It seems the loop is not working as expected. If you have a more optimal solution O(1), please share. Thanks!

const dupArr = ["a", "b", "c", "d", "d",'dog']

function transformSearchFields(fields) {
  let noDupes = new Set(fields)
  const searchData = new Set(['dog', 'a'])

  // iterate over noDupes set and check if element is in the searchData set. If it is, remove the element from the noDupes set
  noDupes.forEach(element => {
    if (element in searchData) {
        noDupes.delete(element)
    }
  })

  return [...noDupes]
  }
// desired output: ["b", "c", "d"]

I expected the loop to remove values that were in the searchData set

>Solution :

To check if a value is "in" a Set, use .has()

.has

The has() method returns a boolean indicating whether an element with the specified value exists in a Set object or not.

In your case this would be:

if (searchData.has(element)) {

Updated snippet

const dupArr = ["a", "b", "c", "d", "d", 'dog']

function transformSearchFields(fields) {
  let noDupes = new Set(fields)
  const searchData = new Set(['dog', 'a'])

  // iterate over noDupes set and check if element is in the searchData set. If it is, remove the element from the noDupes set
  noDupes.forEach(element => {
    //console.log(element, element in searchData, searchData.has(element))
    if (searchData.has(element)) {
      noDupes.delete(element)
    }
  })

  return [...noDupes]
}
console.log(transformSearchFields(dupArr));

There are other methods filter data (as provided in other answer, so not repeated here).