Java LocalDateTime Duration fundamental

Here’s my code:

// check if the time within 10 mins
if (Duration.between(listOfAppointment.get(Integer.parseInt(indicator) - 1).getDateTimeOfAppointment(), LocalDateTime.now()).compareTo(Duration.ofMinutes(10)) < 0) { 

    try {

        listOfAppointment.get(Integer.parseInt(indicator) - 1).setCheckIn(true);
        System.out.println("The check-in has been done! Let's see your PT!");
        break;

    } catch (Exception e) {

        System.out.println("Invalid input, please try again!");
        indicator = console.nextLine();
    }

} else {
    System.out.println("It seems that it's still too early, please wait util 10 minutes left!");
    break;
}

All related packages imported and I tried with sample date like one day after but still it always printed out the try-block content, please help me resolve it. Thanks!

>Solution :

It seems that you’re trying to check if the time of an appointment is within 10 minutes from the current time, and if so, set the check-in flag to true, isn’t it?. However, there is an issue in your code. You are using a try-catch block unnecessarily and breaking the loop within the try block. Here is what I believe to be a corrected version of your code:

// Assuming you have already parsed the indicator as an integer
int index = Integer.parseInt(indicator) - 1;
LocalDateTime appointmentTime = listOfAppointment.get(index).getDateTimeOfAppointment();
LocalDateTime now = LocalDateTime.now();
Duration timeDifference = Duration.between(appointmentTime, now);

if (timeDifference.compareTo(Duration.ofMinutes(10)) < 0) {
    listOfAppointment.get(index).setCheckIn(true);
    System.out.println("The check-in has been done! Let's see your PT!");
} else {
    System.out.println("It seems that it's still too early, please wait until 10 minutes are left!");
}