Java non-greedy (?) regex to match string

String poolId = "something/something-else/pools[name='test'][scope='lan1']";
String statId = "something/something-else/pools[name='test'][scope='lan1']/stats[base-string='10.10.10.10']";

Pattern pattern = Pattern.compile(".+pools\\[name='.+'\\]\\[scope='.+'\\]$");

What regular expression should be used such that

pattern.matcher(poolId).matches()

returns true whereas

pattern.matcher(statsId).matches()

returns false?

Note that

1. something/something-else is irrelevant and can be of any length
2. Both name and scope can have ANY character including any of \, /, [, ] etc
3. stats[base-string='10.10.10.10'] is an example and there can be anything else after /

I tried to use the non-greedy ? like so .+pools\\[name='.+'\\]\\[scope='.+?'\\]$ but still both matches return true

>Solution :

You can use

.+pools\[name='[^']*'\]\[scope='[^']*'\]$

See the regex demo. Details:

• .+ – any one or more chars other than line break chars as many as possible
• pools\[name=' – a pools[name='string
• [^']* – zero or more chars other than a '
• '\]\[scope=' – a '][scope=' string
• [^']* – zero or more chars other than a '
• '\] – a '] substring
• $ – end of string.

In Java:

Pattern pattern = Pattern.compile(".+pools\\[name='[^']*']\\[scope='[^']*']$");

See the Java demo:

//String s = "something/something-else/pools[name='test'][scope='lan1']"; // => Matched!
String s = "something/something-else/pools[name='test'][scope='lan1']/stats[base-string='10.10.10.10']";
Pattern pattern = Pattern.compile(".+pools\\[name='[^']*']\\[scope='[^']*']$");
Matcher matcher = pattern.matcher(s);
if (matcher.find()){
    System.out.println("Matched!"); 
} else {
    System.out.println("Not Matched!"); 
}
// => Not Matched!