JavaScript: Removing all Objects that are equal in just a single attribute from Array

I have an Array of Geography-Location-Objects of this kind:

   let markers = [
   {
    "markerOffset": 10,
    "name": "Plantation",
    "coordinates": ["9.85804","53.5233"]
   },
   {
    "markerOffset": 10,
    "name": "Roasting",
    "coordinates": ["29.85804","50.5233"]
   },
   {
    "markerOffset": 10,
    "name": "Packaging",
    "coordinates": ["29.85804","50.5233"]
   },
{
    "markerOffset": 10,
    "name": "Harbour",
    "coordinates": ["21.85804","51.5213"]
   },
]

How can I filter the array to remove duplicate objects with the same coordinates (such as element 2 and 3) and only leave one entry with the coordinates.

A Set wont work propably because of the differing name: attribute

>Solution :

Simple compare and build a new array. This doesn’t care about the name attribute and just uses the first one that comes along

let markers = [
   { "markerOffset": 10, "name": "Plantation", "coordinates": ["9.85804","53.5233"] },
   { "markerOffset": 10, "name": "Roasting", "coordinates": ["29.85804","50.5233"] },
   { "markerOffset": 10, "name": "Packaging", "coordinates": ["29.85804","50.5233"] },
   { "markerOffset": 10, "name": "Harbour",  "coordinates": ["21.85804","51.5213"] },
]

let results = [];
markers.forEach(marker => {
    if(!results.find(m => m.coordinates[0] === marker.coordinates[0] &&  m.coordinates[1] === marker.coordinates[1] )) results.push(marker);
})

console.log(results);