JS Why Won't This Console.Log Evaluate Properly?

let a=3, b=4, c=5;
console.log(`b > a ` + b>a);
console.log(`c < a ` + c<a);
console.log(`!(a<b)` + !(a<b));

Why is it that the last line is executed with the proper string + the result, but the other two don’t include the string?

>Solution :

It’s because of operator precedence. Arithmetic operators have higher precedence than comparison operators (so you can write things like if (x + y > z)), so

console.log(`b > a ` + b>a);

is equivalent to

console.log((`b > a ` + b) > a);

This logs the result of the comparison between 'b > a 4' and 3.

You want to concatenate the result of the comparison, so you have to write

console.log(`b > a ` + (b > a));

to override the default precedence.

Your last example works as intended because !(a<b) groups the comparison together as a single expression, similar to (b > a) in my rewrite.