**kwargs parameter name has a "." in it creating an error

January 23, 2022

I am trying to pass an argument into a function with **kwargs
allas some of the argument names contain a . and I get an error as code editor expect argument name and don’t recognize it, likely because of the "."

def get_active_offers(**kwargs):
    params = {}
    for args in kwargs:
        params[args]=kwargs.values() 
    response = api_request(params)
    return response


test = get_active_offers(BasicFilters.PriceFrom="1")

is there a way around it (something like an f string for arguments?)

for the moment my solution has been to pass the name of the argument and the value as a list and naming it with a simpler name but I am trying to learn the proper way?

def get_active_offers(**kwargs):
    params = {}
    for args in kwargs.values():
        params[args[0]]=args[1] 
    response = api_request(params)
    return response


test = get_active_offers(argument = ["BasicFilters.PriceFrom","1"])

>Solution :

As one of the comments said, you can pass the argument as a dict:

def get_active_offers(**kwargs):
    params = {}
    for args in kwargs:
        params[args]=kwargs.values() 
    response = api_request(params)
    return response


test = get_active_offers(**{"BasicFilters.PriceFrom":"1"})

The above syntax of using ** with the argument is called "dictionary unpacking"