Locating indices with element 1 and converting to a list in Python

I have an array A. I want to identify all indices with element 1 and print as a list. But I am getting an error. I present the expected output.

import numpy as np

A=np.array([[1, 0, 1, 1, 0, 1, 0, 0, 0, 0, 0, 0]])
A1=np.where(A[0]==1)
A1.tolist()
print(A1)

The error is

in <module>
    A1.tolist()

AttributeError: 'tuple' object has no attribute 'tolist'

The expected output is

[[0, 2, 3, 5]]

>Solution :

A1 = [i for i,x in enumerate(A[0]) if x == 1]

or

A1=list(np.where(A[0]==1)[0])

You have an array inside an array hence A[0]