Making an Armstrong number checker but if condition is not working

I was Making A Armstrong number checker not for only 3 digits numbers for wich i used Math.pow() method but after using it the if else statement is not working also when the condition is true.
Here is the code.

import java.util.Scanner;
import java.lang.Math;
class Main {
 ////////////////////////////////////////////

 ////////////////////////////////////////////
 public static void main(String args[])
{
 System.out.println("Hello world!");
 Scanner sc = new 
 Scanner(System.in);
 int num = sc.nextInt();
 int  numc = num ; 
 double rem = 0;
 double cu = 0;
 int val = 0;
 int val2 = 0;
 
 
 while(num != 0){
  rem = num%10;
  
  while(numc != 0){
   numc /=10;
   int i = 0;
   i++;
   val2 += i; 
  }


  cu = Math.pow(rem,val2 );
  val += cu; 
  num /= 10;
 }


 if(val == numc){
    System.out.println("Yes its a "+val2+"  Armstrong number because its returning " + val+"after Calculations ");
   }
   else{
     System.out.println("No its not a "+val2+" digit Armstrong number because its returning " + val +" after Calculations ");
            
           }
 
}
}
///////////////////////////////////////////

And this is the Compilation of my code

>Solution :

if(val == numc){ – This if part is the root cause of your problem . you are dividing numc by 10 for calculations . So at the end it will become 0 . so you will be checking if val == 0 which goes to the else loop.

So I would suggest to assign the input from the user to another variable which you can use for checking the final if – else part.

Like int input = num and at the end if(val==input){ . This would resolve your issue.