Map A Dictionary With Pandas Column

I have a pandas dataframe column province which contains USA states and Canada province names in both uppercase and lowercase

df.province

Output

MANITOBA
Alberta
CA
OH

A dictionary to map all Canada province values

ca_provinces_dic = {
    'Newfoundland and Labrador': 'NL',
    'Prince Edward Island': 'PE',
    'Nova Scotia': 'NS',
    'New Brunswick': 'NB',
    'Quebec': 'QC',
    'Ontario': 'ON',
    'Manitoba': 'MB',
    'Saskatchewan': 'SK',
    'Alberta': 'AB',
    'British Columbia': 'BC',
    'Yukon': 'YT',
    'Northwest Territories': 'NT',
    'Nunavut': 'NU',
}

How to map all the province values with their respective short form using pandas that handles the case matching issue as well?

For example –
I want to compare all the province column values (in lowercase) with all the dictionary keys (in lowercase) and based on the match I will apply the appropriate short form for the province column values (only where applicable)

My current attempt to this problem.

canada_provinces_dic = {
    'Newfoundland and Labrador': 'NL',
    'Prince Edward Island': 'PE',
    'Nova Scotia': 'NS',
    'New Brunswick': 'NB',
    'Quebec': 'QC',
    'Ontario': 'ON',
    'Manitoba': 'MB',
    'Saskatchewan': 'SK',
    'Alberta': 'AB',
    'British Columbia': 'BC',
    'Yukon': 'YT',
    'Northwest Territories': 'NT',
    'Nunavut': 'NU',
}


def handle_state(data_attr):
  for k, v in canada_provinces_dic.items():
      if data_attr.strip().lower() == k.lower():
        return canada_provinces_dic[k]
  else:
    return data_attr

df['state'] =  df.state.apply(handle_state)

>Solution :

Use Series.map and Series.fillna:

First convert your dict to keys in lowercase:

In [638]: ca_provinces_dic = {k.lower():v for k,v in ca_provinces_dic.items()}

In [659]: df['province'] = df['province'].str.lower().map(ca_province_dict).fillna(df['province'])

In [660]: df
Out[660]: 
  province
0       MB
1       AB
2       CA
3       OH