I have following three lists:
paths = ["c:/path/path", "d:/path/path"]
folder_one = ["fol1", "fol2"]
folder_two = ["folder1", "folder2"]
How can I map these three lists so the output could look like this:
("c:/path/path", "fol1")
("c:/path/path", "fol2")
("d:/path/path", "folder1")
("d:/path/path", "folder2")
So far I have:
somelists = [paths] + [folder_one + folder_two]
for element in itertools.product(*somelists):
print(element)
But it also generate tuple like: ("c:/path/path", "folder1")
Can anyone give me a hint?
>Solution :
This should give what you want:
[f"{p}/{f}" for p, file in zip(paths, (folder_one, folder_two)) for f in file]
>>> ['c:/path/path/fol1',
'c:/path/path/fol2',
'd:/path/path/folder1',
'd:/path/path/folder2']
You can split it up in the following parts:
zip(paths, (folder_one, folder_two))
connect each path to a list of folders (folder_one, folder_two).
Then going over each path and the files in a list:
for p, file in zip(paths, (folder_one, folder_two))
file is here a list with files.
The last part is iterating over each file in the file list:
for f in file
EDIT
Sorry I taught that you want the paths, changed for the desired output:
[(p,f) for p, file in zip(paths, (folder_one, folder_two)) for f in file]
>>> [('c:/path/path', 'fol1'),
('c:/path/path', 'fol2'),
('d:/path/path', 'folder1'),
('d:/path/path', 'folder2')]