modify query function in Sequelize

October 7, 2022

I’m learning "Sequelize".
I went through documentation and got this code somewhere else.

Model = require('../models/Salesman')
module.exports.creareSalesman = (req, res, next) => {
Model.create(req.body).then(
    result => {
        res.status.json({data: result})
    }).catch(err => console.log(err))
}

but I want this in the below structure,

Model = require('../models/Salesman')
module.exports.creareSalesman = (req, res, next) => {
    Model.create(req.body, function (result, err) {
        if (err) {
            console.log(err)
        }
        else {
            res.status.json({data: result})
        }
    });
}

I tried this,.it didn’t send the response. But inserted the data correctly to db.
How to get the response in this case.?

>Solution :

The Model.create method returns a Promise, and does not have a callback parameter.
So you either handle the Promise with then:

module.exports.creareSalesman = (req, res, next) => {
  Model.create(req.body)
    .then((result) => {
      res.status.json({ data: result });
    })
    .catch((err) => console.log(err));
};

Or use async await:

module.exports.creareSalesman = async (req, res, next) => {
    try {
      const result = await Model.create(req.body);
      res.status.json({ data: result });
    } catch (err) {
      console.log(err);
    }
  };