Multiple args in custom print

I define debug_print():

def debug_print(info):
  print("[FOO] :",info)

I expect I can call like normal print like this:

name = 'Ujang'
debug_print(name, 'is winner!'); # I expect [FOO] : Ujang is winner!

But it gave me error

TypeError: debug_print() takes 1 positional argument but 2 were given

I tried redefine debug_print parameter with using pointer symbol
def debug_print(*info) but it’s showing tuple format.

# output
[FOO] : ('Ujang', 'is winner!')

>Solution :

You can use join() function without map() as follows:

def debug_print(*info):
  print("[FOO] :", ' '.join(info))
  
name = 'Ujang'
debug_print(name, 'is winner!')

Output:

[FOO] : Ujang is a winner!

Also, as @KellyBundy suggested, you can take advantage of the print() function and pass *info as a parameter, so the print function will automatically convert all of its values to string:

def debug_print(*info):
  print("[FOO] :", *info)
  
name = 'Ujang'
debug_print(name, 'is winner!')