Multiple replace of literals by digits

November 8, 2022

I need to replace multiple literals by digits in a string like "FF432423FA112". "A"=0, "B"=1 etc. I’ve tried to do it in a loop like but it didn’t work. Tried also with char array

String test = "FF432423FA112";
String[] letters = {"A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z"};
    for (int i=0; i<letters.length; i++) {
        newStr = test.replace(letters[i],i);
    }

>Solution :

That is because you forget to use newStr.replace, every time loop will generate the last test.replace copy character

        String test = "FF432423FA112";
        String[] letters = {"A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z"};
        String newStr = test;
        for (int i=0; i<letters.length; i++) {
            newStr = newStr.replace(letters[i], i + "");
        }

        System.out.println(newStr);