Multiple unnecessary input appearing when using try except handling for input params

I am trying to make a few params for inputs using try/except so that input is repeated until expected input is given

def inputParams(x,y):
    while x != 1 or x != 2:
        try:
            x = int(input(y))
            if x == 1 or x == 2:
                return x
            else:
                print("Invalid Input")
                inputParams(x, y)
        except:
            inputParams(x, y)

My problem is that when i give an invalid input, the try statement asks me to repeat my input, and even though i give a valid input in the repeated input, it asks me to repeat my input the number of times i gave an invalid input.

Image to show what i mean

As you can see, the input "ffd" is invalid, so the program asks me to repeat my input, but the input of 1 is valid, but the program asks me to repeat my input again, this issue is resolve however, after entering my input for the second time, but number of time i need to repeat my input corresponds with the number of times i gave an invalid input

>Solution :

You don’t need to use recursion. This code works just fine:

def inputParams(x,y):
    while True:
        try:
            x = int(input(y))
            if x == 1 or x == 2:
                return x
            else:
                print("Invalid Input")
        except:
            pass

If you want to use recursion, delete the while loop, or use return inputParams(x, y) rather than just inputParams(x, y) to exit the function:

def inputParams(x,y):
    try:
        x = int(input(y))
        if x == 1 or x == 2:
            return x
        else:
            print("Invalid Input")
            return inputParams(x, y)
    except:
        return inputParams(x, y)