n is 0 after passing it as an argument to the function, What seems to be the problem here?

Here the question is to put all the zeroes to the end of the array.
I’ve written the below code, but after passing {arr,n} to the pushzero() function, when I try to print the array, it does nothing, and the value of n changes to zero after calling the pushzero() function.

#include <bits/stdc++.h>

using namespace std;

void pushzero(int arr[], int n) {   
    for (int i = 0; i < n; i++) {   
        for (int j = 0; j < i + 1; j++) {
            if (arr[j] == 0) {
                swap(arr[j+1], arr[j]);
            }
        }
    }
}

int main() {
    int arr[] = { 2, 6, 0, 0, 1, 9, 0, 8, 0 };
    int n = sizeof(arr) / sizeof(arr[0]);
    
    for (int i = 0; i < n; i++) {
        cout << arr[i] << " " << "\n";
    }
    pushzero(arr, n);
    
    for (int j = 0; j < n; j++) { // n is 0 here
        cout << arr[j] << " ";
    }
    return 0;
}

>Solution :

You could do it by using 0 as a pivot element and whenever you see a non zero element you will swap it with the pivot element. So all the non zero element will come at the beginning.

void pushzero(int arr[], int n) {  
    int j =0; 
    for (int i = 0; i < n; i++) {   
        if(arr[i] != 0) {
            swap(arr[i], arr[j]);
            j++;
        }
    }
}

Demo: https://godbolt.org/z/oMdxfdWjG