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Pandas: Filter rows depending on number of occurrences of target string

Given this sample data:

temp
a. b
a b
a. b. c
ab.c

I only want to keep rows in column temp that has only one period, so the above data would become:

temp
a. b
ab.c

Is there a way to do this with a lambda function, preferably?

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>Solution :

You can try this:

df.loc[df['temp'].str.count(r'\.').eq(1)]

   temp
0  a. b
3  ab.c
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