pandas: how to get pandas.compare() to return all columns of the other row?

With dataframes df_a and df_b, how do I return the difference (meaning, the data in other at variance with self) as complete rows (e.g., all columns)? If I do

first = {
    'Name': ['Bob', 'Mike', 'Alex'],
    'Job': ['Forklift Operator', 'Forklift Operator', 'Master Forklift Operator']
}

second = {
    'Name': ['Bob', 'Mike', 'Allen'],
    'Job': ['Forklift Operator', 'Forklift Operator', 'Master Forklift Operator']

df_a = pd.DataFrame(first)
df_b = pd.DataFrame(second)

df_c = df_a.compare(df_b)
print(df_c)

that gives me

    Name
    self  other
2   Alex  Allen

What I would like to be able to get is the entire row from other that does not match the left:

    Name                       Job
2  Allen  Master Forklift Operator

>Solution :

You can use:

df_b.loc[df_a.compare(df_b).index]

Output:

    Name                       Job
2  Allen  Master Forklift Operator