Password requirements

I’m trying to declare this string as Invalid but in an input like this:

59G71341 or 8pjf7h14sx13 or 60s1v344

My output is getting approved through my string if statement and is getting listed as Valid.

Could anyone guide me to why its passing through my if statement and labeling Valid!!

I haven’t learned how to use a debugger yet so bare with me.

Task description:

Declare a Boolean variable named goodPasswd. Use goodPasswd to output "Valid" if secretStr contains no more than 5 digits and secretStr’s length is greater than or equal to 5, and "Invalid" otherwise.

Ex: If the input is 80796, then the output is:
Valid

Ex: If the input is XBdg, then the output is:
Invalid

#include <iostream>
using namespace std;

int main()
{
    string secretStr;

    bool goodPasswd = false;
    cin >> secretStr;
    int counter = 0;
    for (int i = 0; i < secretStr.length(); ++i)
    {
        if ((secretStr[i] >= 0) && (secretStr[i] <= 9))
        {
            ++counter;
        }
    }  //approves string if both true
    if ((counter <= 5) && (secretStr.length() >= 5))
    {
        goodPasswd = true;
    }
    else
    {
        goodPasswd = false;
    }

    if (goodPasswd)
    {
        cout << "Valid" << endl;
    }
    else
    {
        cout << "Invalid" << endl;
    }

    return 0;
}

>Solution :

if ((secretStr[i] >= 0) && (secretStr[i] <= 9))

should be

if ((secretStr[i] >= '0') && (secretStr[i] <= '9'))

0 and 9 are integers, but you are comparing characters, so you need to use the characters '0' and ‘9‘, or you could just use the isdigit function.

if (isdigit(secretStr[i]))

isdigit is declared in #include <cctype>

Not related to your question but you don’t need to goodPasswd variable. Simply

if (counter <= 5 && secretStr.length() >= 5)
{
    cout << "Valid" << endl;
}
else
{
    cout << "Invalid" << endl;
}

seems a bit cleaner to me.