perl oneliner to read file line by line and skip some word by position

Given a log like this:

2022-03-30 21:05:00.266 +0200 CEST debug  Mylog 

is it possible to parse it (with a oneliner command) and skip, for example 3rd 4th and 5th
so that I would get this output?

2022-03-30 21:05:00.266 Mylog  

>Solution :

perl -lane 'splice @F, 2, 3; print "@F"'

• -l removes newlines from input and adds them to output
• -n reads the input line by line, running the code for each line
• -a splits each line on whitespace into the @F array
• splice removes three elements from @F starting with position 2 (numbering starts at 0)