I am trying to generate an error message in my HTML if one of these two things are happening, however the appropriate message is displaying the HTML, but I’m also given a warning for having a undefined variable.
How would I fix it with how I am doing it?
Code:
$tweet = "{$_POST['tweet']}";
$errorOne = "Error: Your tweet must be less than 140 characters.";
$errorTwo = "Error: Your tweet must not be blank.";
if(strlen($tweet) > 140){
$errorOneOutput = $errorOne;
}elseif(empty($tweet)){
$errorTwoOutput = $errorTwo;
}
?>
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<meta http-equiv="X-UA-Compatible" content="IE=edge">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<title></title>
</head>
<body>
<?= $errorOneOutput ?>
<?= $errorTwoOutput ?>
</body>
</html>
I have tried using exit() in my PHP block instead of embedded HTML but then that doesn’t generate the HTML. I specifically need the error message to be displayed within the HTML like this:
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<meta http-equiv="X-UA-Compatible" content="IE=edge">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<title>Challenge 3</title>
</head>
<body>
<br />
<b>Warning</b>: Undefined variable $errorOneOutput in <b>C:\xampp\htdocs\WEBD\Challenges\Challenge 3 - Twitter Challenge\insert.php</b> on line <b>29</b><br />
Error: Your tweet must not be blank.</body>
</html>
I also know that I can just echo out my errors, but again those would be above the HTML and not within it.
>Solution :
The issue is you’re trying to print a variable you haven’t initialised:
<?= $errorOneOutput ?>
<?= $errorTwoOutput ?>
To initialise these variables, add this to the top of your php file:
$errorOneOutput = "";
$errorTwoOutput = "";