Pick position of a list based on the position of another list in Python

December 21, 2022

Im a Python beginner and also new to Stackoverflow cant seem to find a solution to this problem and I have been looking around in weeks. It’s an assignment and we cant use inbuild Python functions.

I want to find the position of an item in list A and choose the same position from list B. The item in list A should not be equal to zero. Once done, I have to add the corresponding value in B.
Eg:

A = [0,0,1,1]
B = [25,9,8,3]

A should result in position 2,3
B therefore equals to 8,3
8+3 = 11

Below is what I have tried so far

binary = [0,1,1,0,0,0]
decimal = [32,16,8,4,2,1]
output_decimal = []
for position in range(0, len(binary)):
    if binary[position] !=0:
        position = position+1
        print(position)

>Solution :

I think you got it. From your code, simply register the positions in the separate list that you created and then sum it up

binary = [0,1,1,0,0,0]
decimal = [32,16,8,4,2,1]
output_decimal = []
for position in range(0, len(binary)):
    if binary[position] !=0:
        output_decimal.append(decimal[position])
# to add everything
print(sum(output_decimal))

Output gives you: 16+8 = 24