Please help to translate code Pascal to JS?

February 9, 2022

I have this code in Pascal:

var
K,N,i,j:integer;
begin
readln(K,N);
for i:=1 to trunc(sqrt(K)) do
if K mod i = 0 then
begin
if i*(K div i+1)+(K div i)*(i+1)=N then writeln(i+1,' ',K div i+1);
end;
end.

And this my code in JavaScript:

const a = [1000, 2065]

function Sum(K, N) {
  for (i = 1; i < Math.trunc(Math.sqrt(K)); i++) {
    if (K % i === 0 && i * (Math.floor(K / (i) + 1) + Math.floor(K / i) * (i + 1)) === N) {
      break;
    }
  }
  console.log(i + 1, Math.floor(K / (i)) + 1)
}
Sum(a[0], a[1]);

Can you help why my answers in JavaScript are wrong?

>Solution :

Not exactely sure what you’re trying to achieve but this javascript code produces the same output (26, 41) as your pascal version does:

See onlinegdb.com!

const K = 1000, N = 2065;
for (let i=1; i<Math.trunc(Math.sqrt(K)); i++)
  if (K % i === 0)
    if (i*(K / i+1)+(K / i)*(i+1) === N)
        console.log(i+1, K / i+1);

I think you have messed something up with the brackets in Math.floor or something similar.