pointer type operator VS const bool operator precedence

#include <cstdint>
#include <iostream>

struct a_struct {
    int64_t* le_int;
    bool not_ok;

    a_struct() : le_int{ new int64_t(0) }, not_ok{ false } {}
    ~a_struct() { delete le_int; }

    operator bool() const {
        return !not_ok;
    }

    operator int64_t* () {
        return le_int;
    }
};

int main(int argc, char** argv) {

    a_struct s;
    s.not_ok = true;
    if (!s)//<-
        std::cout << "o no." << std::endl;

    else if (s.not_ok)
        std::cout << "waddu heck?" << std::endl;

    return 0;
}

In this example the !s resolution prefers the int64_t*() operator over the const bool() operator.

Why?

>Solution :

Since your object s is not const, it prefers the non-const way of calling the type cast operator. So, removing the const from your bool type cast operator does the trick.