Print all unique pairs of a string array without repeating on other side in Swift

Have searched all stackoverflow, couldn’t find answer for my particular question-

Array is
["Codex1", "Codex2", "Codex3"]

Requirement is
["Codex1", "Codex2"] , ["Codex2", "Codex3"] , ["Codex1", "Codex3"]

Or if elements are 4,
["Codex1", "Codex2", "Codex3", "Codex4"]

should print
["Codex1", "Codex2"] , ["Codex3", "Codex4"] , ["Codex1", "Codex3"], ["Codex1", "Codex4"],["Codex2", "Codex3"], ["Codex2", "Codex4"]

and similarly so on. Its not a requirement that it should print in [String, String] , it can be other data structure.

>Solution :

You can try

let arr = ["Codex1", "Codex2", "Codex3", "Codex4"]
var res = [[String]]()
arr.indices.forEach { item in
    ((item+1)..<arr.count).forEach {
        res.append([arr[item],arr[$0]])
    }
}
print(res)