print statement only when the condition is CONSECUTIVELY met 3 times in a row

I’m currently making a guessing game where user can get a congrats statement if they guess correctly 3 times in a row or a hint statement if they guesses incorrectly 3 times in a row. If user makes two correct guesses and one incorrect guess the count will reset and vice versa for incorrect guesses. the goal is for the right/wrong guess to be 3 times in a row for the statement to print

Here is what I have

count = 0

rightGuess = 0

wrongGuess = 0

die1 = random.randint(1,6)



guess = int(input('Enter guess: '))

if guess == die1:
     
rightGuess += 1
     
print('Good job')
     
     if rightGuess == 3:
          print('You guessed three times in a row!')


if guess != die1:
      
wrongGuess += 1
      
print('Uh oh wrong answer')
     
      if wrongGuess == 3:
           print("Hint: issa number :)")

This works but it displays the text whenever the user reaches 3 wrong or right guesses even if it’s not in a row. Please help

>Solution :

You just have to reset the opposite variable to 0 when incrementing either of them.

count = 0
consecutiveRightGuess = 0
consecutiveWrongGuess = 0
die1 = random.randint(1, 6)
guess = int(input('Enter guess: '))

if guess == die1:
    consecutiveWrongGuess = 0
    consecutiveRightGuess += 1
    print('Good job')
    if consecutiveRightGuess == 3:
        print('You guessed three times in a row!')

if guess != die1:
    consecutiveRightGuess = 0
    consecutiveWrongGuess += 1
    print('Uh oh wrong answer')
    if consecutiveWrongGuess == 3:
        print("Hint: issa number :)")