Print the nth step of a Generator in an easy way

I want to know if there is a better and cleaner way of printing the 3rd step of a generator function.
Currently I have written the following code

def imparesgen():
  n = 0
  while n<200: 
    n=n+2
    yield n

gen = imparesgen()

y = 0
for x in gen:
  y+=1
  if y == 3:
    print(x)

This worked, but, is there maybe a simpler way of doing this? Without the use of a list.

>Solution :

From Itertools recipes:

def nth(iterable, n, default=None):
    "Returns the nth item or a default value"
    return next(islice(iterable, n, None), default)

Applied to your example:

import itertools

def imparesgen():
  n = 0
  while n<200:
    n=n+2
    yield n

gen = imparesgen()

print(next(itertools.islice(gen, 3, None)))