prints the content of an array through a function

this is the code:
the code needs to send the array to the function and the function will print but it seems there is run time error

#include <stdio.h>
#include <string.h>

void printArray(char* p, int len)
{
    for (p; p < p + len; p++)
    {
        printf("%c", *p);
    }
    printf("\n");
}

int main(void)
{
    char* msg = "hi jyegq meet me at 2 :)"; 
    printArray(msg, strlen(msg));
    getchar();
    return 0;
}

>Solution :

for (p; p < p + len; p++)

This condition is all the time true, as you do not modify len and p is identical with p, even after mutatations. You need to define a new pointer q that is initially equal to p and mutate only q.

void printArray(char* p, int len)
{
    for (char *q = p; q < p + len; q++)
        printf("%c", *q);
    printf("\n");
}

It is better to define char const* p, as there is no reason to mutate p.