Produce this list [0, 2, 6, 12, 20, 30, 42, 56, 72, 90] using list comprehension syntax

I can produce the list [0, 2, 6, 12, 20, 30, 42, 56, 72, 90] using the following code:

x = []
y = 0
for i in range(2,21,2):
    x.append(y)
    y += i

However I’m not sure how to convert this into list comprehension syntax of the form

[expression for value in iterable if condition ]

>Solution :

You can assign to y inside the comprehension, using an assignment expession, i.e. using :=:

y = 0
x = [y := y + i for i in range(0,20,2)]

Alternatively, you can make use of the fact that these are doubles of triangular numbers, and then you don’t need y (but multiplication):

x = [i * (i + 1) for i in range(10)]