Program only allows login if the email matches the last registered user. C++

So, I’ve been trying to make this program this entire day and I got stuck at this big problem where I cannot it to log into the account by verifying with the previously existing data in my txt file of registered users.

NOTE: userEmail is inheritted from another class and is defined.

This is my login function:

void logIn() { // ! Function to log into an existing account.
system("cls");
string loginEmail, loginPassword;
bool verifyEmail = false;
cout<<"\n~\t~\tLogging into an existing account..\t~\t~\n";
cout<<"\nEmail: ";
cin.ignore();
getline(cin,loginEmail);
ifstream checkEmail("registeredUsers.txt");
ifstream open("registeredUsers.txt");
while(checkEmail>>userEmail && loginEmail.find('@') != string::npos && loginEmail.length() > 6) {
    if (userEmail == loginEmail) {
        verifyEmail = true;
    }
    else {
        verifyEmail = false;
    }
}
if (verifyEmail == true) {
    cout<<"\nPassword: ";
getline(cin,loginPassword);
}
else {
    cout<<"Email not found.. Please register a new account.\n";
    system("pause");
    return;
}
system("pause");
}

Lets say if my registeredAccounts.txt has lines
12345@gmail.com
testing@gmail.com
fortified@gmail.com
Then it would only ever continue to the password section if I typed fortified@gmail.com in my program and it would not let me proceed if i typed any other emails.

>Solution :

Break out of the while loop immediately after you set verifyEmail = true. There is no need to check additional email addresses if you have already found a match. As it is, your code goes on to check non-matching email addresses, setting verifyEmail back to false.

For example:

while(checkEmail>>userEmail && loginEmail.find('@') != string::npos && loginEmail.length() > 6) {
    if (userEmail == loginEmail) {
        verifyEmail = true;
        break;
    } else {
        verifyEmail = false;
    }
}

Now, you don’t actually need to set verifyEmail to false. So you can just use:

while(checkEmail>>userEmail && loginEmail.find('@') != string::npos && loginEmail.length() > 6) {
    if (userEmail == loginEmail) {
        verifyEmail = true;
        break;
    }
}