Python 3 program finding smallest number between 4 inputs

January 16, 2024

I am learning Python and got stuck on a task with creating program that will find smallest number of 4 using only if and else. No elif, no min, no list etc, only base if and else

I dont really have any ideas, I only made 2 programs which use elif, but they dont work too:

x=int (input())
b=int (input())
c=int (input())
d=int (input())
if x<b and  x<c and x<d:
    print (x)
elif b<x and b<c and b<d:
    print (b)
elif c<x and c<b and c<d:
    print (c)
else: print (d)

File "c:\Python\r.py", line 1, in <module>
x=int (input())
  ^^^^^^^^^^^^^
ValueError: invalid literal for int() with base 10

and

a=int (input())
b=int (input())
c=int (input())
d=int (input())
n1=int
n2=int
if a<b:
    a=n1
else: b=n1
if c<d:
    c=n2
else: d=n2
n1=int
n2=int
if n1<n2:
    print (n1)
else: print (n2)

TypeError: '<=' not supported between instances of 'type' and 'type'

>Solution :

You can do it using nested if statements to test all the possibilities.

n1 = int(input())
n2 = int(input())
n3 = int(input())
n4 = int(input())

if n1 < n2:
    if n1 < n3:
        if n1 < n4:
            print(n1)
        else:
            print(n4)
    else:
        if n3 < n4:
            print(n3)
        else:
            print(n4)
else:
    if n2 < n3:
        if n2 < n4:
            print(n2)
        else:
            print(n4)
    else:
        if n3 < n4:
            print(n3)
        else:
            print(n4)