Python bitwise operation on condtion statement 'unexpected' behavior

I’m new to python programing. While solving a practice problem and experimenting with bitwise operation, I ran into unexpected output:

index = 0
time = '?'

print(index)
print(index == 1)
print(time[0].isnumeric())
print(index == 1 & time[0].isnumeric())
print(index == 1 and time[0].isnumeric())

Output:

0
False
False
True
False

As far as I understand:

• False and False should result in False : Boolean operation
• False & False should result in False : Bitwise operation

Based on the above understanding when I performed bitwise operation on condition statement I getting the output as ‘True’. When I change to boolean operation, I get the expected output of ‘False’.

Can someone please explain this behavior, I’m sure that I’m missing something.
Thanks.

>Solution :

Bitwise operations have similar precedence to other mathematical operations. Just as you would want 1 + 2 == 3 to be interpreted as (1 + 2) == 3 rather than 1 + (2 == 3),

index == 1 & time[0].isnumeric()

is interpreted as

index == (1 & time[0].isnumeric())

i.e.

0 == (1 & False)

In Python, False == 0 and 1 == True, so 1 & False == 1 & 0 == 0.

On the other hand,

index == 1 and time[0].isnumeric()

is interpreted as

(index == 1) and time[0].isnumeric()

just as you would want a == b and c == d to be interpreted as (a == b) and (c == d) rather than a == (b and c) == d.