Given the following dict:
mydict={'id': '123', 'name': 'Bob', 'age': '30','city': 'LA'}
I would like to transform this dictionary into a nested dict, where "id" key is kept, but all other (arbitary) keys are then packed into a nested dict. Hence the output should be like:
nestdict={'id':'123','data':{'name': 'Bob', 'age': '30','city': 'LA'}}
What I have tried was using dict.pop but this returns a list , and also using defaultdict from collections, but this did not work.
from collections import defaultdict
nestdict = defaultdict(dict)
nestdict[mydict['id']] = mydict[['name'],['age'],['city']]
nestdict
>Solution :
If you don’t want to mutate the original mydict,
>>> mydict = {'id': '123', 'name': 'Bob', 'age': '30','city': 'LA'}
>>> d = {'id': mydict['id'], 'data': {k: v for k, v in mydict.items() if k != "id"}}
{'id': '123', 'data': {'name': 'Bob', 'age': '30', 'city': 'LA'}}
If mutating mydict (since we pop out id) is OK,
>>> mydict = {'id': '123', 'name': 'Bob', 'age': '30','city': 'LA'}
>>> d = {'id': mydict.pop('id'), 'data': mydict}
{'id': '123', 'data': {'name': 'Bob', 'age': '30', 'city': 'LA'}}