Python give *args default value

Inside my class I have:

def refresh(self, func = None, *args):
    if not func:
        return
    new_data = func(*args)
    self.set_text(new_data)

But I have 2 problems:

1. What if func doesn’t take any parameters? Why can’t I do *args = None?
   like I want to do something like this:

   MEDevel.com: Open-source for Healthcare and Education

   Collecting and validating open-source software for healthcare, education, enterprise, development, medical imaging, medical records, and digital pathology.

   Visit Medevel

   def refresh(self, func = None, *args = None):
       if not func:
           return
       if *args:
           new_data = func(*args)
       else:
           new_data = func() # func doesn't take any parameters
       self.set_text(new_data)
   

2. When I try to run my code before the edits I get:

   TypeError: function takes 0 positional arguments but 1 were given

   Why is that?

Here is my main:

def hello_world():
    return 'hello'

tmp2 = LLabel('Hi There!')
tmp2.refresh(hello_world, None)

>Solution :

None is an argument of NoneType. You can try it simply by running the hello_world function by itself.

def hello_world():
    return 'hello'
hello_world(None)

Which will result in the following error: TypeError: hello_world() takes 0 positional arguments but 1 was given.

Hence run the refresh method, with only one argument – the function you want to pass in:

def hello_world():
    return 'hello'
tmp2 = LLabel('Hi There!')
tmp2.refresh(hello_world)

Therefore the original refresh method can stay the same:

def refresh(self, func = None, *args):
    if not func:
        return
    new_data = func(*args)
    self.set_text(new_data)