python: index of list1 equal to index of list2

I have 2 lists , they are the same length and in correct order, what i need(i think) is that index of list1 is equal to index of list2 and print the list2 content at that index.

this is what i have so far:

id = [10610, 12772, 10611, 13434, 13397, 13854]

name = ['sarah', 'john', 'mark', 'james', 'jack']

userid = int(input('enter user ID: '))
ind = id.index(userid)
 
if userid in id:
    print(ind)
else:
    print('wrong ID')

output:

enter user ID: 13434
3

what i want it to do is, to print the content thats at the same index in "name" list, in this case its "james"

thanks

>Solution :

well what the comments said and change it like the following too :

    id = [1, 2, 3, 4, 5, 6]

    name = ['sarah', 'john', 'mark', 'james', 'jack']

    userid = int(input('enter user ID: '))

    if userid in id:
        ind = id.index(userid) #notice this statement is inside the if and not outside
        print(name[ind])
    else:
        print("wrong id")

if you try to use inden(..) before checking if the userid (the one they entered) is in the id , then you will get ValueError: <some-numer> is not in list

so its better to do it inside the if