Python pandas using an If..elif..else with multiple or

I’m looking to use something simialr to .isin instead of multiple or’s in this code:

def func(row):
    if row['Office'] == 'USA' or row['Office'] == 'UK' or row['Office'] == 'Aus' or row['Office'] == 'Can':   
        return 1        
    else:
        return 2
    
office_data['Area'] = office_data.apply(func, axis=1)

>Solution :

If using Python +3.10, you can use the match - case in replace of IF statements:

def func(row):
  match row['Office']:
    case 'USA':
      return 1

    case 'UK':
      return 1

    case 'Aus':
      return 1

    case 'Can':
      return 1

    case _:
      return 0

For your case, I would recommend using a dictionary with the possible candidates, like this:

def func(row):
  valid_options = ['USA', 'UK', 'Aus', 'Can']
  if row['Office'] in valid_options: return 1
  return 0