Python print first instance of a file line search

December 1, 2021

I am parsing a .desktop file is python. I wrote the following to find the name of a app to launch.

                 o2 = self.name 
                 #create a temp file so that i can... 
                 tmp = tempfile.NamedTemporaryFile() 
                 with open(tmp.name, 'w') as f: 
                         f.write(o2) 
                 #use readline for a grep like function 
                 with open(tmp.name) as f: 
                         for line in f.readlines(): 
                                 if 'Name=' in line:

Note: self.name is a string version of the. Desktop file.. The thing is every time I do the search it finds the last item in a search, I’ll use alacritty as an example.

 
 Name=Alacritty 
 GenericName=Terminal 
 Comment=A fast, cross-platform, OpenGL terminal emulator 
 StartupWMClass=Alacritty 
 Actions=New; 
  
 [Desktop Action New] 
 Name=New Terminal 
 Exec=alacritty

I want it to print out the first Name= you see but it prints out the last one under [Desktop Action New] how can I fix this?

>Solution :

So you want to print the first 'Name=' but not the second one ?
If it is what you are trying to do, just break the loop after printing the first 'Name='

                 o2 = self.name 
                 #create a temp file so that i can... 
                 tmp = tempfile.NamedTemporaryFile() 
                 with open(tmp.name, 'w') as f: 
                         f.write(o2) 
                 #use readline for a grep like function 
                 last_line = None
                 with open(tmp.name) as f: 
                         for line in f.readlines(): 
                                 if 'Name=' in line:
                                         print(line)
                                         #maybe do some more staff, then :
                                         break

That will prevent the second 'Name=' from being printed.