Python regex match n characters before the keyword

I have a dataframe column looks like this

data
Membership 1 year
Individual - 10 years:
Membership 2019-2024

I want to extract the number before the keyword ‘year’.
I’d like to get output:

data                      contract_years
Membership 1 year         1
Individual - 10 years:    10
Membership 2019-2024

I tried
\d{2}+(?=year) which is obviously wrong. Any suggestion will be really helpful, thanks.

>Solution :

df['contract_years'] = df['data'].str.extract('(\d+) year')