Python Regex: Split on first occurrence of letter

I’m trying to split a string into an initial numeric component and the remaining components, using the first occurrence of a letter as the delimiter, so for example:

"123b" -> ["123", "b"]
"12b7.97ap" -> ["12", "b7.97ap"]

I’m new to regex and I’m having trouble achieving this… The best I could do is:

re.split(r"(\d+)", string)

But this returns:

["", "123", "b"]
["", "12", "b", "7", ".", "97", "ap"]

For the two examples above. I suppose I could then combine all the elements after index 1 into a single string, but I’m sure there’s a better way… Thanks in advance for any help!

>Solution :

One possibility, first matching digits and then matching the rest:

import re

for s in "123b", "12b7.97ap":
    print(re.findall('\d+|.+', s))

Output:

['123', 'b']
['12', 'b7.97ap']