Python str not list

I wanted to obtain array of int like [1,2,3]

but got [dict_values([1]),dict_values([2]),dict_values([3])]

taken_employee_ids_dict = [{‘id’: 1}, {‘id’: 2}, {‘id’: 3}]

my code

taken_employee_ids = [str(taken_employee_ids_list.values()) for taken_employee_ids_list in taken_employee_ids_dict]

in_values_check = ','.join(str(id) for id in taken_employee_ids)

And then in_values_check should go in:

qry = "SELECT CONCAT(first_name, ',', surname) AS full_name, id \
            FROM employees \
            WHERE date_terminated IS NULL \
            and id NOT IN " + "(" + in_values_check + ")" \
            " ORDER BY first_name, surname ASC"

sorry i am new to python thanks

>Solution :

You can do it with lambda or list comprehension

With Lambda,

taken_employee_ids_dict = [{'id': 1}, {'id': 2}, {'id': 3}]
in_values_check = list(map(lambda x : x['id'], taken_employee_ids_dict))
print(in_values_check)

With List Comprehension,

taken_employee_ids_dict = [{'id': 1}, {'id': 2}, {'id': 3}]
in_values_check = [dic['id'] for dic in taken_employee_ids_dict]
print(in_values_check)

Output:

[1, 2, 3]