Title pretty much says it all, using Oracle SQL, I’d like to get, as quickly as possible, three records that share an ID from a very large table. The rows are not duplicates, they share one ID (rID) but differ in another (mID).
One approach I know I could do (that would be very slow) would be to load the first say 1000 records into a C# program, then execute a COUNT query to count the number of records with each ID until I hit one with 3 records and return that ID. I know this is a terrible approach but should give an idea of what I want to get out of this.
I’ve tried using GROUP BY, and this would work but would be unacceptably slow, I don’t care about the state of the rest of the table, I just need a single ID that has three records. Ideally I’d do something like a GROUP BY that would stop after finding the first ID with three or more records and just return that one. There are over a million records in the table so efficiency is important.
>Solution :
What you describe translates to:
select the_id
from the_table
group by the_id
having count(*) >= 3
fetch first row only;
This should be as fast as it gets. You can help Oracle by providing an index on the id. That’s about it.