I have the following dataset:
id = 1:5
col1 = c("john", "henry", "adam", "jenna", "peter")
col2 = c("river B8C 9L4", "Field U9H 5E2 PP", "NA", "ocean A1B 5H1 dd", "dave")
col3 = c("matt", "steve", "forest K0Y 1U9 hu2", "NA", "NA")
col4 = c("Phone: 111 1111 111", "Phone: 222 2222", "Phone: 333 333 1113", "Phone: 444 111 1153", "Phone: 111 111 1121")
my_data = data.frame(id, col1, col2, col3, col4)
id col1 col2 col3 col4
1 1 john river B8C 9L4 matt Phone: 111 1111 111
2 2 henry Field U9H 5E2 PP steve Phone: 222 2222
3 3 adam NA forest K0Y 1U9 hu2 Phone: 333 333 1113
4 4 jenna ocean A1B 5H1 dd NA Phone: 444 111 1153
5 5 peter dave NA Phone: 111 111 1121
I found this REGEX code that recognizes the following pattern – this can then be wrapped into a function:
apply(my_data, 1, function(x) gsub('(([A-Z] ?[0-9]){3})|.', '\\1', toString(x)))
[1] "B8C 9L4" "U9H 5E2" "K0Y 1U9" "A1B 5H1" ""
Once this has been done, is there any way to extend this code such that
- Once the row/column with the REGEX condition has been identified, the entire contents of this row/column are extracted?
For example this, would then look like this:
[1] "river B8C 9L4 " Field U9H 5E2 PP" "forest K0Y 1U9 hu2" "ocean A1B 5H1 dd"
>Solution :
Try
library(stringr)
na.omit(apply(my_data[-1], 1, \(x)
{x <- x[x != "NA"]
x1 <- x[(!str_detect(x, "Phone"))]
x1[str_count(x1, "\\w+") > 1][1]
})
-output
[1] "river B8C 9L4" "Field U9H 5E2 PP"
[3] "forest K0Y 1U9 hu2" "ocean A1B 5H1 dd"