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Reg expression to exclude string with % char in it

I want to match all the instances of filter[ … ] but excluding the ones that have a % char in them:

filter[first_name%0]=Tim&filter[first_name]=Tom&filter[first_name]=Bob

The /filter\[.*?\]/i gets all of the instances but how do I exclude the one with % in it?

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>Solution :

You can use

filter\[[^\][%]*]

See the regex demo

Details

  • filter\[ – a filter[ string
  • [^\][%]* – zero or more (*) chars that are not equal to ], [ and %
  • ] – a literal ] char.
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