Regex add space in string if the word is longer than 4 characters and have numbers

I try to create a regex with 2 condition:

• if word length more than 4 character
• And if the word contains numbers

I need to add spaces

So like: iph12 return iph12, but iphone12 return iphone 12

I wrote regex

.replace(/\d+/gi, ' $& ').trim()

and this function return in anyway string like iphone 12. I tried to use function

.replace(/(?=[A-Z]+\d|\d+[A-Z])[A-Z\d]{,4}/i, ' $& ').trim()

but without second argument in {,4} it’s not working. So is this possible?

>Solution :

You can use

text.replace(/\b([a-zA-Z]{4,})(\d+)\b/g, '$1 $2')

See the regex demo. Details:

• \b – word boundary
• ([a-zA-Z]{4,}) – Group 1: four or more ASCII letters
• (\d+) – Group 2: one or more digits
• \b – word boundary

See the JavaScript demo:

const texts = ['iphone12', 'iph12'];
const regex = /\b([a-zA-Z]{4,})(\d+)\b/g;
for (const text of texts) {
    console.log(text, '=>', text.replace(regex, '$1 $2'));
}

Output:

iphone12 => iphone 12
iph12 => iph12