Regex – Checking if [x]/[y] y is greater than x

I’m trying to capture [x]/[y] and if y is greater than x using a regex pattern.
The input is in the second column ($2)

Example input:

NAME1 0/1
NAME2 0/2
NAME3 1/2
NAME4 1/3
NAME5 2/2
NAME6 1/1

Output:

NAME1 0/1
NAME2 0/2
NAME3 1/2
NAME4 1/3

What would be the right approach using awk?

I’ve done so far:

cat pods | grep -v Completed | awk -e '$2 ~ "[0-9]/[0-9]"'

I’m not sure how to proceed or to check if the second [0-9] is greater.

>Solution :

With your shown samples, please try following awk code. Simple explanation would be, in main program splitting 2nd field using awk‘s split function and splitting 2nd field into array named arr using field separator /, then checking condition if 2nd element of array is GREATER than 1st element then printing that line.

awk  '{split($2,arr,"/")} arr[2]>arr[1]' Input_file

OR As an alternate solution one could also use:

awk -F' |/' '$3>$2' Input_file