Regex | Find 3 character length word starts with specific char '%'

Using Regex, I need to find a word within a encoded url query string which matches start with specific char % and word must be 3 chars length long including starting specific char %.

A sample is following:

Sam+JS%2C+COSP+Lepar-+Happy+Search+%28ENG%29+%5B320kbps%5D+%5B2019%5D+%7BYMB%9D

First char would always be %

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Second char would always be a number [0-9]

Third char would be either a number OR an alphabet (either in small or caps)

Result from above sample like be:

%2C %28 %29 %5B %5D %5B etc..

Hope problem is very clear.

>Solution :

Your regex should be something like that

['%']{1}[0-9]{1}[a-zA-Z0-9]{1}

Explain the code:

['%']{1} => matches the character %
[0-9]{1} => matches a single character in the range between 0 and 9
[a-zA-Z0-9]{1} => matches a single alphabet character or number between 0 and 9

You could build and test regex on regex101