Regex find URL with the first extension

I have string like below

string = 'https://somewebsite.com/itesr0824/products/YYA-002/fdrop-tQ?position=6'

How can I find

'https://somewebsite.com/itesr0824'

with regex?

I’ve tried

re.sub('[^https://somewebsite.com/[a-zA-Z0-9].+$','',string)

but it only finds

'https://somewebsite.com/itesr0824/products/YYA'

>Solution :

import re

string = 'https://somewebsite.com/itesr0824/products/YYA-002/fdrop-tQ?position=6'

x = re.sub('https:\/\/somewebsite\.com/[\w\d]+','',string)

# where: \w - any word character, \d - any digit, + - one or more

print(x)

Prints

/products/YYA-002/fdrop-tQ?position=6