I am trying to validate a regex which
- allows 10 digits
- if digit starts with 672 then it should only allow total 9 digits
I have tried below regex
/^\d{10}$|^(672)\d{6}$/
https://regex101.com/r/0ahnKx/1
It works for 10 digits but if number starts with 672 then also it allows 10 digits.
Could anyone help how can I fix this?
Thanks!
>Solution :
First of all, the capturing group in your regex is redundant, it would make sense to wrap the part of the pattern between ^ and $ to only use single occurrences of the anchors.
To fix the issue, you need to make sure the first three digits matched by \d{10} are not 672, and you can achieve that with a negative lookahead:
/^((?!672)\d{10}|672\d{6})$/
/^(?:(?!672)\d{10}|672\d{6})$/
See the regex demo. Details:
^– start of string(?:– start of a group:(?!672)\d{10}– no672substring check is triggered and then ten digits are matched
|– or672\d{6}–672and six digits
)– end of the group$– end of string.