Regex: Look for a specific word after the first backslash occurrence

I’m wanting to use regex to look for the word "bacon" after the first "/" occurrence.

For example:

Should return true:

console.log('1 - ', myRegexFunction('www.bacondelivery.com/weekly-bacon-delivery/'));
console.log('2 - ', myRegexFunction('www.bacondelivery.com/daily-bacon-delivery/'));
console.log('3 - ', myRegexFunction('www.bacondelivery.com/bacon-of-the-month-club/'));

Should return false:

console.log('4 - ', myRegexFunction('www.bacondelivery.com/'));
console.log('5 - ', myRegexFunction('www.bacondelivery.com/?some_param'));
console.log('6 - ', myRegexFunction('www.bacondelivery.com/about/'));
console.log('7 - ', myRegexFunction('www.bacondelivery.com/contact-us/'));

Here’s what I currently have:

function myRegexFunction(url) {
  var regex = new RegExp("^([a-z0-9]{5,})$");
  if (regex.test(url)) {
      return true;
  } else {
      return false;
  }
}

Thanks!

>Solution :

You may use this regex for this:

^[^\/]+\/[^\/]*\bbacon\b.*

RegEx Demo

RegEx Details:

• ^: Start
• [^\/]+: Match 1 or more of any character that is not a /
• \/: Match a /
• [^\/]*: Match 0 or more of any character that is not a /
• \bbacon\b: Match complete word bacon
• .*: Match remaining text on this line

Code:

function myRegexFunction(url) {
  const regex = /^[^\/]+\/[^\/]*\bbacon\b.*/;
  return regex.test(url);
}

console.log('1 - ', myRegexFunction('www.bacondelivery.com/weekly-bacon-delivery/'));

console.log('2 - ', myRegexFunction('www.bacondelivery.com/daily-bacon-delivery/'));
console.log('3 - ', myRegexFunction('www.bacondelivery.com/bacon-of-the-month-club/'));

console.log('4 - ', myRegexFunction('www.bacondelivery.com/'));
console.log('5 - ', myRegexFunction('www.bacondelivery.com/?some_param'));
console.log('6 - ', myRegexFunction('www.bacondelivery.com/about/'));
console.log('7 - ', myRegexFunction('www.bacondelivery.com/contact-us/'));